Integrand size = 10, antiderivative size = 143 \[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}-\frac {x^2}{2 a^2 \arccos (a x)^2}+\frac {2 x^4}{3 \arccos (a x)^2}+\frac {x \sqrt {1-a^2 x^2}}{a^3 \arccos (a x)}-\frac {8 x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)}+\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{3 a^4}+\frac {4 \operatorname {CosIntegral}(4 \arccos (a x))}{3 a^4} \]
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Time = 0.19 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4730, 4808, 4728, 3383} \[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{3 a^4}+\frac {4 \operatorname {CosIntegral}(4 \arccos (a x))}{3 a^4}-\frac {x^2}{2 a^2 \arccos (a x)^2}-\frac {8 x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)}+\frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}+\frac {x \sqrt {1-a^2 x^2}}{a^3 \arccos (a x)}+\frac {2 x^4}{3 \arccos (a x)^2} \]
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Rule 3383
Rule 4728
Rule 4730
Rule 4808
Rubi steps \begin{align*} \text {integral}& = \frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}-\frac {\int \frac {x^2}{\sqrt {1-a^2 x^2} \arccos (a x)^3} \, dx}{a}+\frac {1}{3} (4 a) \int \frac {x^4}{\sqrt {1-a^2 x^2} \arccos (a x)^3} \, dx \\ & = \frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}-\frac {x^2}{2 a^2 \arccos (a x)^2}+\frac {2 x^4}{3 \arccos (a x)^2}-\frac {8}{3} \int \frac {x^3}{\arccos (a x)^2} \, dx+\frac {\int \frac {x}{\arccos (a x)^2} \, dx}{a^2} \\ & = \frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}-\frac {x^2}{2 a^2 \arccos (a x)^2}+\frac {2 x^4}{3 \arccos (a x)^2}+\frac {x \sqrt {1-a^2 x^2}}{a^3 \arccos (a x)}-\frac {8 x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)}-\frac {\text {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\arccos (a x)\right )}{a^4}-\frac {8 \text {Subst}\left (\int \left (-\frac {\cos (2 x)}{2 x}-\frac {\cos (4 x)}{2 x}\right ) \, dx,x,\arccos (a x)\right )}{3 a^4} \\ & = \frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}-\frac {x^2}{2 a^2 \arccos (a x)^2}+\frac {2 x^4}{3 \arccos (a x)^2}+\frac {x \sqrt {1-a^2 x^2}}{a^3 \arccos (a x)}-\frac {8 x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)}-\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{a^4}+\frac {4 \text {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\arccos (a x)\right )}{3 a^4}+\frac {4 \text {Subst}\left (\int \frac {\cos (4 x)}{x} \, dx,x,\arccos (a x)\right )}{3 a^4} \\ & = \frac {x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)^3}-\frac {x^2}{2 a^2 \arccos (a x)^2}+\frac {2 x^4}{3 \arccos (a x)^2}+\frac {x \sqrt {1-a^2 x^2}}{a^3 \arccos (a x)}-\frac {8 x^3 \sqrt {1-a^2 x^2}}{3 a \arccos (a x)}+\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{3 a^4}+\frac {4 \operatorname {CosIntegral}(4 \arccos (a x))}{3 a^4} \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.75 \[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\frac {\frac {a x \left (2 a^2 x^2 \sqrt {1-a^2 x^2}+a x \left (-3+4 a^2 x^2\right ) \arccos (a x)-2 \sqrt {1-a^2 x^2} \left (-3+8 a^2 x^2\right ) \arccos (a x)^2\right )}{\arccos (a x)^3}+2 \operatorname {CosIntegral}(2 \arccos (a x))+8 \operatorname {CosIntegral}(4 \arccos (a x))}{6 a^4} \]
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Time = 0.61 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.80
method | result | size |
derivativedivides | \(\frac {\frac {\sin \left (2 \arccos \left (a x \right )\right )}{12 \arccos \left (a x \right )^{3}}+\frac {\cos \left (2 \arccos \left (a x \right )\right )}{12 \arccos \left (a x \right )^{2}}-\frac {\sin \left (2 \arccos \left (a x \right )\right )}{6 \arccos \left (a x \right )}+\frac {\operatorname {Ci}\left (2 \arccos \left (a x \right )\right )}{3}+\frac {\sin \left (4 \arccos \left (a x \right )\right )}{24 \arccos \left (a x \right )^{3}}+\frac {\cos \left (4 \arccos \left (a x \right )\right )}{12 \arccos \left (a x \right )^{2}}-\frac {\sin \left (4 \arccos \left (a x \right )\right )}{3 \arccos \left (a x \right )}+\frac {4 \,\operatorname {Ci}\left (4 \arccos \left (a x \right )\right )}{3}}{a^{4}}\) | \(114\) |
default | \(\frac {\frac {\sin \left (2 \arccos \left (a x \right )\right )}{12 \arccos \left (a x \right )^{3}}+\frac {\cos \left (2 \arccos \left (a x \right )\right )}{12 \arccos \left (a x \right )^{2}}-\frac {\sin \left (2 \arccos \left (a x \right )\right )}{6 \arccos \left (a x \right )}+\frac {\operatorname {Ci}\left (2 \arccos \left (a x \right )\right )}{3}+\frac {\sin \left (4 \arccos \left (a x \right )\right )}{24 \arccos \left (a x \right )^{3}}+\frac {\cos \left (4 \arccos \left (a x \right )\right )}{12 \arccos \left (a x \right )^{2}}-\frac {\sin \left (4 \arccos \left (a x \right )\right )}{3 \arccos \left (a x \right )}+\frac {4 \,\operatorname {Ci}\left (4 \arccos \left (a x \right )\right )}{3}}{a^{4}}\) | \(114\) |
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\[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\int { \frac {x^{3}}{\arccos \left (a x\right )^{4}} \,d x } \]
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\[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\int \frac {x^{3}}{\operatorname {acos}^{4}{\left (a x \right )}}\, dx \]
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\[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\int { \frac {x^{3}}{\arccos \left (a x\right )^{4}} \,d x } \]
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Time = 0.28 (sec) , antiderivative size = 125, normalized size of antiderivative = 0.87 \[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\frac {2 \, x^{4}}{3 \, \arccos \left (a x\right )^{2}} - \frac {8 \, \sqrt {-a^{2} x^{2} + 1} x^{3}}{3 \, a \arccos \left (a x\right )} + \frac {\sqrt {-a^{2} x^{2} + 1} x^{3}}{3 \, a \arccos \left (a x\right )^{3}} - \frac {x^{2}}{2 \, a^{2} \arccos \left (a x\right )^{2}} + \frac {\sqrt {-a^{2} x^{2} + 1} x}{a^{3} \arccos \left (a x\right )} + \frac {4 \, \operatorname {Ci}\left (4 \, \arccos \left (a x\right )\right )}{3 \, a^{4}} + \frac {\operatorname {Ci}\left (2 \, \arccos \left (a x\right )\right )}{3 \, a^{4}} \]
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Timed out. \[ \int \frac {x^3}{\arccos (a x)^4} \, dx=\int \frac {x^3}{{\mathrm {acos}\left (a\,x\right )}^4} \,d x \]
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